A ball whose kinetic energy is E, is thrown at an angle of `45^(@)` with the horizontal. Its kinetic energy at the highest point of its flight will be :

Options

A. E
B. `(E)/sqrt(2)`
C. `(E)/(2)`
D. zero

Answer

C

Explanation

`E=(1)/(2)mu^(2)`
and `E'=(1)/(2)mu^(2)cos^(2)45^(@)=Exx(1)/(2)=(E)/(2)`