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A projectole fired with initial velocity...

A projectole fired with initial velocity u at some angle `theta` has a range `R`. If the initial velocity be doubled at the same angle of projection, then the range will be

A

half

B

one-fourth

C

two times

D

four times

Text Solution

Verified by Experts

The correct Answer is:
D
Range of projectile `=(u^(2)sin 2theta)/(g)`
`because` Range `prop u^(2)`
`therefore` When u is doubled, range becomes 4 times.
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