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The horizontal range and the maximum hei...

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is :

A

`theta=tan^(-1)(2)`

B

`theta=45^(@)`

C

`theta=tan^(-1)((1)/(4))`

D

`theta=tan^(-1)(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`R=H_("max")rArr(2u^(2)sin theta cos theta)/(g)=(u^(2)sin^(2)theta)/(2g)`
`rArr tan theta=4 rArr theta=tan^(-1)(4)`
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ALLEN-MOTION IN A PALNE-EXERCISE-1
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