A battery of six cells each of e.m.f. 2V...

A battery of six cells each of e.m.f. 2V and internal resistance `0.5Omega` is being charged by D.C. mains of e.m.f. 220V by using an external resistance of `10Omega` what will be the charging current.

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To find the charging current in the given circuit, we will follow these steps: ### Step 1: Determine the total EMF of the battery The total EMF (E) of the battery is the sum of the EMFs of the individual cells. Since there are 6 cells, each with an EMF of 2V: \[ E = 6 \times 2V = 12V \] ...

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