For the given network calculate current I and `I_(2)`.

Answer

`5 m`

Explanation

Velocity of block A just before collision `v_(A) = sqrt(u_(A)^(2) - 2mugx) = sqrt(16 - 2 (1)/(15) (10) (2)) = sqrt((40)/(3))`
Velocity of Block B just after collision `v_(B) = v_(A) = sqrt((40)/(3))`
Velocity of Block A just after collision `= 0`
Total dsitance travelled by block B `= (v_(B)^(2))/(2mug) = (40//3)/(2(2)/(15) (10)) = 5m`