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If not current flows through the galvano...

If not current flows through the galvanometer the find the value of unknown resistance X. Assume that resistance per unit length of wire AB is 0.2 `Omega//cm`.
then also calculate total current given by battery.

Text Solution

Verified by Experts

For balanced condition `(X)/( R_(AJ))=(2)/(R_(JB))`
`R_(AJ)=0.02xx60=1.2Omega,R_(JB )=0.02xx4 0= 0.8O mega rArr(X)/(1.2)=(2)/(0.8)rArrX=3Omega`
Current given by the battery `I=(4)/(R_(eq))`
where `R_(eq)=((3+2)(1.2+0.8))/(3+2+1.2+0.8)=(10)/(7)Omega` so `I=(4xx7)/(10)=2.8A`
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