If `10^(6)` electrons/s are flowing through an area of cross section of `10^(-4) m^(2)` then the current will be:-

Explanation

To solve the problem, we need to calculate the current flowing through a cross-sectional area when a certain number of electrons are passing through it per second. Here are the steps to find the solution:

### Step 1: Identify the number of electrons and the charge of one electron
We are given that \( n = 10^6 \) electrons are flowing per second. The charge of a single electron is approximately \( e = 1.6 \times 10^{-19} \) Coulombs.

### Step 2: Calculate the total charge flowing per second
The total charge \( Q \) flowing per second can be calculated using the formula:
\[ Q = n \cdot e \]
Substituting the values:
\[ Q = 10^6 \cdot (1.6 \times 10^{-19}) \]
Calculating this gives:
\[ Q = 1.6 \times 10^{-13} \text{ Coulombs} \]

### Step 3: Calculate the current
Current \( I \) is defined as the amount of charge flowing per unit time. Since we are considering the charge flowing in one second, we can express current as:
\[ I = \frac{Q}{t} \]
Where \( t = 1 \) second. Therefore:
\[ I = \frac{1.6 \times 10^{-13}}{1} = 1.6 \times 10^{-13} \text{ Amperes} \]

### Final Answer
The current flowing through the area of cross-section is:
\[ I = 1.6 \times 10^{-13} \text{ Amperes} \]

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