A `1Omega` voltmeter has range 1V find the additional resistance which has to join in series in voltmeter to increase the range of voltmeter to 100V :-

Answer

`3.96 m`

Explanation

`COME rArr mg (h + x_(0)) = (1)/(2) kx_(0)^(2)`
`rArr mg(0.24 + 0.01)`
`= (1)/(2) k(0.01 xx 0.01)` ….(i)
& `mg (h + 0.04) = (1)/(2)k(0.04)^(2)` …..(ii)
Equation (i) divided by (ii) `h = 3.96 m`