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A metal wire of resistance R is cut into...

A metal wire of resistance R is cut into three equal pieces that are then connected side by side to form a new wire, the length of which is equal to one third of the original length. The resistance of this new wire is:-

A

R

B

3R

C

`(R)/(9)`

D

`(R)/(3)`

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The correct Answer is:
To solve the problem of finding the resistance of the new wire formed by cutting a metal wire of resistance \( R \) into three equal pieces and connecting them side by side, we can follow these steps: ### Step 1: Understand the Original Wire's Resistance The resistance \( R \) of the original wire can be expressed using the formula: \[ R = \frac{\rho L}{A} \] where: - \( \rho \) is the resistivity of the material, - \( L \) is the length of the wire, - \( A \) is the cross-sectional area of the wire. ### Step 2: Determine the Resistance of Each Piece When the wire is cut into three equal pieces, each piece will have: - Length: \( \frac{L}{3} \) - Cross-sectional area: \( A \) The resistance \( R_p \) of each piece can be calculated as: \[ R_p = \frac{\rho \left(\frac{L}{3}\right)}{A} = \frac{R}{3} \] ### Step 3: Calculate the Total Resistance of the New Configuration When the three pieces are connected side by side (in parallel), the total resistance \( R_f \) of the new wire can be calculated using the formula for resistors in parallel: \[ \frac{1}{R_f} = \frac{1}{R_p} + \frac{1}{R_p} + \frac{1}{R_p} = 3 \cdot \frac{1}{R_p} \] Substituting \( R_p = \frac{R}{3} \): \[ \frac{1}{R_f} = 3 \cdot \frac{1}{\frac{R}{3}} = 3 \cdot \frac{3}{R} = \frac{9}{R} \] ### Step 4: Solve for the Total Resistance Now, taking the reciprocal to find \( R_f \): \[ R_f = \frac{R}{9} \] ### Conclusion The resistance of the new wire formed by connecting the three pieces side by side is: \[ R_f = \frac{R}{9} \]
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