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The resistance of galvanometer is g ohm ...

The resistance of galvanometer is g ohm and the range is 1 volt. The value of resistance used to convert it into a voltmeter of ragne 10 volt is:-

A

9G

B

G

C

`(1)/(9)G`

D

`10G`

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The correct Answer is:
To convert a galvanometer into a voltmeter, we need to add a series resistance to it. The formula to calculate the required resistance \( R \) for a voltmeter is given by: \[ R = \frac{V}{I} - g \] where: - \( V \) is the maximum voltage range of the voltmeter, - \( I \) is the current through the galvanometer when the maximum voltage is applied, - \( g \) is the resistance of the galvanometer. ### Step-by-Step Solution: 1. **Identify the given values:** - The resistance of the galvanometer \( g \) (in ohms). - The maximum range of the galvanometer is 1 volt. - The desired range of the voltmeter is 10 volts. 2. **Calculate the current through the galvanometer:** The current \( I \) when the galvanometer is at its full scale (1 volt) can be calculated using Ohm's Law: \[ I = \frac{V_g}{g} = \frac{1}{g} \] where \( V_g \) is the voltage across the galvanometer. 3. **Substitute the values into the resistance formula:** Now, we substitute \( V = 10 \) volts (the desired range) and \( I = \frac{1}{g} \) into the formula for \( R \): \[ R = \frac{10}{\frac{1}{g}} - g \] 4. **Simplify the equation:** \[ R = 10g - g = 9g \] 5. **Conclusion:** The value of the resistance used to convert the galvanometer into a voltmeter of range 10 volts is: \[ R = 9g \] ### Final Answer: The required resistance is \( 9g \) ohms.
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