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P,Q is a uniform wire of resistance 2000...

P,Q is a uniform wire of resistance `2000Omega` and M is the md point of PQ. A voltmeter of resistance `1000Omega` is connected between P and M. the reading of the voltmeter, when, the potential differences applied between PQ is 150volt will be

A

150volt

B

100volt

C

75volt

D

50volt

Text Solution

Verified by Experts

The correct Answer is:
4

`I=(V)/(R_(eq))=(150)/(1500)=(1)/(10)A because rArr V=(1)/(20)xx1000=50` volt volt
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