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A cell of emf E and internal resistance ...

A cell of emf E and internal resistance r supplies current for the same time t through external resistance `R_(1)` and `R_(2)` separately. If the heat developed in both the cases is the same, then the internal resistance r will be

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`[(E)/(R_(1)+r)]^(2)R_(1)=[(E)/(R_(2)+r)]^(2)R_(2)rArr r=sqrt(R_(1)R_(2))`
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