For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature `theta` of the hot junction (when the cold junction is at `0^(@)C`)are found to satisfy approximately the parabola equation `V=alpha theta+(1)/(2)betatheta^(2)` with
`alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2)` (copper-iron)
`alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2)` (chromel-alumel)
Which of the two thermocouples would you use to measure temperature in the range of a about `500^(@)C` to `600^(@)C`?

Explanation

To determine which thermocouple to use for measuring temperatures in the range of 500°C to 600°C, we need to analyze the given equations for the thermoelectric emf (V) of both thermocouples.

### Step-by-Step Solution:

1. **Understand the Equation**: The thermoelectric emf is given by the equation:
\[ V = \alpha \theta + \frac{1}{2} \beta \theta^2 \]
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