The thermo emf of a thermocouple , one junction of which is kept at `0^(@)C` , is given by `varepsilon=at+bt^(2)` where a and b constants of the thermocouple . Calculate the neutral temperature and peltier and Thomson coefficients.

The rate of increase of thermo-emf with temperature at the neutral temperature of a thermocouple

Above neutral temperature, thermo e.m.f. in a thermocouple

The displacement (x) of a particle as a function of time (t) is given by x=asin(bt+c) Where a,b and c are constant of motion. Choose the correct statemetns from the following.

The position of a particle as a function of time t, is given by x(t)=at+bt^(2)-ct^(3) where a,b and c are constants. When the particle attains zero acceleration, then its velocity will be :

If the cold junction of thermocouple is kept at 0^(@)C and the hot junction is kept at T^(@)C , then the relation between neutral temperature (T_(n)) and temperature of inversion (T_(i)) is

The emf varepsilon of a Cu-Fe thermocouple varies with the temperature theta of the hot junction (cold junction at 0^(@)C ), as varepsilon(mu V)=14 theta-0.02 theta^(2) Determine the neutral temperature.

In variation of specific heat capcity of a substance with temperature is given by C =A + BT ^(2) , where A and B are constnts and T is the temperature, Calculate the mean specific heat in a temperature range T = 0 to T =T and the specific heat at the mid-point T//2.

The thermo emf E of a thermocouple is found to vary wit temperature T of the junction (cold junction is 0^(@)C ) as E=40T-(T^(2))/(20) The temperature of inversion for the thermocouple is

The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference q in .^(@)C between the two junctions according to the relation E=30 theta-(theta^(2))/(15) The neutral temperature for the thermo-couple will be:-

The temperature of inversion of a thermocouple is 620^(@)C and the neutral temperature is 300^(@)C . What is the temperature of cold junction?