A compound of vanadium has a magnetic moment of `1.73BM`. Work out the electronic configuration of vanadium in the compound

Explanation

To determine the electronic configuration of vanadium in the compound with a magnetic moment of 1.73 Bohr magneton (BM), we can follow these steps:

### Step 1: Understand the relationship between magnetic moment and unpaired electrons
The magnetic moment (μ) is related to the number of unpaired electrons (n) in an atom by the formula:
\[ \mu = n(n + 2) \text{ Bohr magneton} \]
Given that μ = 1.73 BM, we can set up the equation:
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