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Highest size will be of...

Highest size will be of

A

`Br^(-)`

B

`I`

C

`I^(-)`

D

`I^(+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which species has the highest size among bromide ion (Br⁻), iodine (I), iodide ion (I⁻), and iodine positive (I⁺), we can follow these steps: ### Step 1: Understand the Effect of Charge on Size - Negative ions (anions) have more electrons than protons, resulting in increased electron-electron repulsion. This leads to an increase in the size of the ion. - Positive ions (cations) have fewer electrons than protons, resulting in decreased electron-electron repulsion and a smaller size. **Hint:** Remember that anions are larger than their neutral atoms, and cations are smaller than their neutral atoms. ### Step 2: Compare the Species - **Bromide ion (Br⁻)**: This ion has gained an electron, making it larger than neutral bromine (Br). - **Iodine (I)**: This is the neutral atom and serves as a baseline for comparison. - **Iodide ion (I⁻)**: This ion has gained an electron, making it larger than neutral iodine (I). - **Iodine positive (I⁺)**: This ion has lost an electron, making it smaller than neutral iodine (I). **Hint:** Identify which species are anions and cations, and recall how gaining or losing electrons affects size. ### Step 3: Analyze the Group Trend - In the periodic table, as you move down a group, the size of the atoms/ions increases due to the addition of electron shells. - Bromine (Br) is above iodine (I) in the periodic table, meaning that bromine is smaller than iodine. **Hint:** Use the periodic table to determine the relative positions of the elements and how that affects their sizes. ### Step 4: Compare the Sizes of Anions - Between bromide ion (Br⁻) and iodide ion (I⁻), since iodine is below bromine in the periodic table, the iodide ion will be larger than the bromide ion. **Hint:** Compare the sizes of the anions based on their positions in the periodic table. ### Conclusion - The order of size from largest to smallest is: I⁻ > Br⁻ > I > I⁺. - Therefore, the species with the highest size is the **iodide ion (I⁻)**. **Final Answer:** The highest size will be of **iodide ion (I⁻)**.
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ALLEN-QUANTUM NUMBER & PERIODIC TABLE-EXERCISE
  1. A neutral atom of an element has two K, eight L, nine M and two N elec...

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  2. The size of the following species increases in the order

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  3. Highest size will be of

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  4. Element Cu has two oxidation states Cu^(+1) & Cu^(+2) the right order ...

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  5. The correct order of increasing atomic size of element N F Si & P.

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  6. The correct order of atomic or ionic size

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  7. ln which of the following electronic configuration ionisation energy w...

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  8. The correct order of second ionisation potential of C, N, O and F is:

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  9. The ionization energy will be maximum for the process.

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  10. The correct order of second I.P.

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  11. Amongst the following, the incorrect statement is

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  12. The process(es) requiring the absorption of energy is/are:

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  13. Electron affinities of O,F,S and Cl are in the order.

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  14. Increasing order of Electron affinity for following configuration. (...

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  15. Highest electron affinity is shown by

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  16. The outer shell configuration of the most electronegative element is

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  17. In the following which configuration element has maximum electronegat...

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  18. On the Pauling's EN scale, the element next to F is ""

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  19. Bond distance C-F in (CF(4)) & Si-F in (SiF(4)) are respective 1.33 Å...

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  20. Which one is not correct order of electro negativity.

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