In the following which configuration element has maximum electronegativity.

Options

A. `1s^(2),2s^(2)2p^(5)`
B. `1s^(2),2s^(2)2p^(6)`
C. `1s^(2),2s^(2)2p^(4)`
D. `1s^(2),2s^(2)2p^(6),3s^(2),3p^(3)`

Answer

To determine which element has the maximum electronegativity based on the given electronic configurations, we can follow these steps:

### Step 1: Understand Electronegativity
Electronegativity is the tendency of an atom to attract electrons in a chemical bond. The most electronegative elements are found in the upper right corner of the periodic table, particularly in Group 17 (the halogens).

**Hint:** Remember that electronegativity increases across a period and decreases down a group in the periodic table.

### Step 2: Identify the Given Electronic Configurations
The question mentions an electronic configuration of NH2NP5. This configuration corresponds to the outer shell of an atom.

**Hint:** Break down the electronic configuration to identify the element it represents.

### Step 3: Determine the Element from the Configuration
The electronic configuration NH2NP5 indicates that the element has 5 electrons in its outermost shell (p orbital). This corresponds to the element fluorine (F), which has the electronic configuration of 1s² 2s² 2p⁵.

**Hint:** Look for the element in the periodic table that matches the given configuration.

### Step 4: Compare Electronegativity Values
Fluorine is known to have the highest electronegativity value of 4.0 on the Pauling scale. Other elements, such as chlorine, bromine, and iodine, have lower electronegativity values compared to fluorine.

**Hint:** Familiarize yourself with the electronegativity values of common elements, especially those in the halogen group.

### Step 5: Conclusion
Since fluorine has the highest electronegativity among all elements, the answer to the question is that the element with the maximum electronegativity is fluorine.

**Final Answer:** Fluorine (F) has the maximum electronegativity.

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