Home
Class 11
CHEMISTRY
Assertion: The first ionisation energy o...

Assertion: The first ionisation energy of `Be` is greater than that of `B`.
Reason: 2p-orbital is lower in energy than 2s-orbital.

A

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.

B

Staterment-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.

C

Statement-1 is true, statement-2 is false.

D

Statement-1 is false, statement-2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the assertion and reason provided in the question, we will break it down step by step. ### Step 1: Understand the Assertion The assertion states that the first ionization energy of Beryllium (Be) is greater than that of Boron (B). **Explanation**: - Beryllium has an atomic number of 4 and its electronic configuration is \(1s^2 2s^2\). - Boron has an atomic number of 5 and its electronic configuration is \(1s^2 2s^2 2p^1\). - The first ionization energy is the energy required to remove the outermost electron from an atom. ### Step 2: Compare the Ionization Energies - For Beryllium, the outermost electrons are in the 2s orbital (2 electrons). - For Boron, the outermost electrons are in the 2s and 2p orbitals (2 in 2s and 1 in 2p). - Removing an electron from Beryllium results in a stable configuration (like that of Helium), while removing an electron from Boron leads to a half-filled 2p orbital, which is less stable. **Conclusion**: The first ionization energy of Beryllium is indeed greater than that of Boron because it is energetically more favorable to remove an electron from Boron. ### Step 3: Understand the Reason The reason states that the 2p-orbital is lower in energy than the 2s-orbital. **Explanation**: - According to the Aufbau principle, the energy levels of orbitals increase in the order of \(1s < 2s < 2p\). - This means that the 2s orbital is actually lower in energy than the 2p orbital. ### Step 4: Evaluate the Reason Since the reason provided is incorrect (the 2p orbital is higher in energy than the 2s orbital), we conclude that while the assertion is correct, the reason is not. ### Final Conclusion - The assertion is **true**: The first ionization energy of Be is greater than that of B. - The reason is **false**: The 2p orbital is not lower in energy than the 2s orbital. Thus, the correct answer is that the assertion is true, but the reason is false. ---
Promotional Banner

Topper's Solved these Questions

  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-MAIN EXERCISE|24 Videos
  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos
  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos
  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 05(B)|8 Videos

Similar Questions

Explore conceptually related problems

Assertion: The first ionization energy of Be is greater than that of B. Reason: 2p-orbital is lower in energy than 2s-orbital.

Assertion: The first ionization energy of Be is greater than that of B. Reason: 2p-orbital is lowerr in energy than 2s-orbital.

The hydration energy of Mg^(+2) is greater than that of

4s orbitals has less energy than 3d orbital

4s orbitals has less energy than 3d orbital

Why is the ionisation energy of beryllium greater than that of Li and B?

The ionisation energy of nitrogen is more than that of oxygen because

In multi-electron atom 4s-orbital is lower in energy than

In multi-electron atom 4s-orbital is lower in energy than

The ionisation energy of potassium is lower than that of sodium. Give reason.

ALLEN-QUANTUM NUMBER & PERIODIC TABLE-EXERCISE
  1. Choose the s-block element from the following:

    Text Solution

    |

  2. Among the following which species is/are paramagnetic (i) Sr^(2+) ...

    Text Solution

    |

  3. It each orbital can hold a maximum of three electrons, the number of e...

    Text Solution

    |

  4. Which of the following clement has highest metallic character

    Text Solution

    |

  5. The electronic configuration of an clement is 1s^(2), 2s^(2), 2p^(6), ...

    Text Solution

    |

  6. the number of d- electrons in Mn^(2+) is equal to that of :

    Text Solution

    |

  7. Which of the following is correct order of EA.

    Text Solution

    |

  8. Which of the following are correct

    Text Solution

    |

  9. If Aufbau's principle and Hund's rule were not followed.

    Text Solution

    |

  10. In halogen, which of the following properties increase from iodine to ...

    Text Solution

    |

  11. Amongst the following statements, which is/are correct?

    Text Solution

    |

  12. Select the correct statements (s)

    Text Solution

    |

  13. Statement-1 : The groundstate configuration of Cr is [Ar] 3d^(5) 4s^(1...

    Text Solution

    |

  14. Assertion: The first ionisation energy of Be is greater than that of B...

    Text Solution

    |

  15. Statement-1 : IE(1) ofN is greater than 0 . Statement-2: N-atom is b...

    Text Solution

    |

  16. Statement-1 : First electron gain enthalpy is alway -ve for an element...

    Text Solution

    |

  17. Statement-1: Ionization potential of Sn is less than Pb. Statement-2...

    Text Solution

    |

  18. Statement-1 : Electron gain enthalpy of Cl is largest in periodic tabl...

    Text Solution

    |

  19. Match the column :

    Text Solution

    |

  20. Minimum number of electrons having m(s)=(-1/2) in Cr is ""

    Text Solution

    |