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The exradii of a triangle r(1),r(2),r(3)...

The exradii of a triangle `r_(1),r_(2),r_(3)` are in HP , then the sides a,b,c are

A

in HP

B

in AP

C

in GP

D

none of these

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The correct Answer is:
To solve the problem, we need to show that if the exradii \( r_1, r_2, r_3 \) of a triangle are in Harmonic Progression (HP), then the sides \( a, b, c \) of the triangle are in Arithmetic Progression (AP). ### Step-by-Step Solution: 1. **Understanding Exradii**: The exradii \( r_1, r_2, r_3 \) of a triangle can be expressed as: \[ r_1 = \frac{\Delta}{s - a}, \quad r_2 = \frac{\Delta}{s - b}, \quad r_3 = \frac{\Delta}{s - c} \] where \( \Delta \) is the area of the triangle and \( s \) is the semi-perimeter given by \( s = \frac{a + b + c}{2} \). 2. **Condition for Harmonic Progression**: Since \( r_1, r_2, r_3 \) are in HP, we can use the property of HP which states that: \[ \frac{1}{r_1}, \frac{1}{r_2}, \frac{1}{r_3} \text{ are in AP} \] This means: \[ 2 \cdot \frac{1}{r_2} = \frac{1}{r_1} + \frac{1}{r_3} \] 3. **Substituting the Exradii**: Substituting the expressions for \( r_1, r_2, r_3 \): \[ 2 \cdot \frac{s - b}{\Delta} = \frac{s - a}{\Delta} + \frac{s - c}{\Delta} \] 4. **Clearing the Denominator**: Multiply through by \( \Delta \) (assuming \( \Delta \neq 0 \)): \[ 2(s - b) = (s - a) + (s - c) \] 5. **Simplifying the Equation**: Expanding and simplifying: \[ 2s - 2b = s - a + s - c \] \[ 2s - 2b = 2s - (a + c) \] 6. **Rearranging the Terms**: Cancel \( 2s \) from both sides: \[ -2b = - (a + c) \] Thus, we have: \[ 2b = a + c \] 7. **Conclusion**: The equation \( 2b = a + c \) indicates that the sides \( a, b, c \) are in Arithmetic Progression (AP). ### Final Answer: If the exradii \( r_1, r_2, r_3 \) of a triangle are in HP, then the sides \( a, b, c \) are in AP.
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