Find the number of solutions of `tanx + secx = 2cosx` in `[0,2pi]`

Explanation

To solve the equation \( \tan x + \sec x = 2 \cos x \) in the interval \( [0, 2\pi] \), we will follow these steps:

### Step 1: Rewrite the equation using sine and cosine
We start by rewriting the tangent and secant functions in terms of sine and cosine:
\[ \tan x = \frac{\sin x}{\cos x} \quad \text{and} \quad \sec x = \frac{1}{\cos x} \]
Thus, we can rewrite the equation as:
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