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(i) Show that (log 9)/2 + 2 log 6 +(log ...

(i) Show that `(log 9)/2 + 2 log 6 +(log 81)/4 - log 12 = 3 log 3` .

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To show that \(\frac{\log 9}{2} + 2 \log 6 + \frac{\log 81}{4} - \log 12 = 3 \log 3\), we will simplify the left-hand side step by step. ### Step 1: Rewrite \(\log 9\) and \(\log 81\) We know that: \[ \log 9 = \log(3^2) = 2 \log 3 \] \[ ...
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