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Solve for x:(a) log(0.3)(x^(2)+8) gt log...

Solve for `x:(a) log_(0.3)(x^(2)+8) gt log_(0.3)(9x)`, b) `log_(7)( (2x-6)/(2x-1)) gt 0`

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### Step-by-Step Solution #### Part (a): Solve for \( x \) in the inequality \( \log_{0.3}(x^2 + 8) > \log_{0.3}(9x) \) 1. **Remove the logarithm**: Since the base of the logarithm (0.3) is less than 1, we need to reverse the inequality when we remove the logarithm. \[ x^2 + 8 < 9x \] ...
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