A car moves at a velocity 2.24 `km h^(-1)` in first minute, at 3.60 `km h^(-1)` in the second minute and at 5.18 `km h^(-1)` in the third minute. Calculate the average velocity in of car in this interval of time.

Explanation

Distance travelled in first minute `" " s_1 = v_1 xx t_1 = 2.24xx (1)/(60)` km
Distance travelled in second minute `" "s_2 = v_2 xx t_2 = 3.60 xx (1)/(60)` km
Distance travelled in third minute `" "s_3 = v_3 xx t_3 = 5.18xx (1)/(60)` km
Total distance travelled, `s= s_1 + s_2 + s_3 = (2.24)/(60) + (3.60)/(60) + (5.18)/(60) = (11.02)/(60)` km
Total time taken, `t = 1+1 +1 = 3 min = (1)/(20)` h
`therefore ` average velocity `= (s)/(t) = (11.02 )/(60) xx (20)/(1) = 3.67` km/h