The velocity of a particle is given by `v=(4t^(2)-4t+3)m//s` where t is time in seconds. Find its acceleration at t=1 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

If v=(t^(2)-4t+10^(5)) m/s where t is in second. Find acceleration at t=1 sec.

The position of a particle is expressed as vecr = ( 4t^(2)hati + 2thatj) m. where t is time in second. Find the acceleration of the particle.

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The velocity of a particle is given by v=(2t^(2)-3t+10)ms^(-1) . Find the instantaneous acceleration at t = 5 s.

A particle moves in a circle of radius 20 cm. Its linear speed is given by v = (3t^(2) +5t) where t is in second and v is in m/s. Find the resultant acceleration at t = 1s.

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

The position of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

If the displacement of a particle is givne by s=((1)/(2)t^(2)+4sqrtt)m . Find the velocity and acceleration at t = 4 seconds.

The angular displacement of a particle is given by theta = t^4 +t^3 +t^2 +1 where ‘t’ is time in seconds. Its angular velocity after 2 sec is