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For a particle moving with constant acce...

For a particle moving with constant acceleration, prove that the displacement in the `n^(th)` second is given by
`s_(n^(th)) = u + (a)/(2)(2n-1)`

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To prove that the displacement in the `n^(th)` second for a particle moving with constant acceleration is given by the formula: \[ s_{(n^{th})} = u + \frac{a}{2}(2n - 1) \] where: - \( s_{(n^{th})} \) is the displacement in the `n^(th)` second, ...
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