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A pebble is thrown vertically upwards fr...

A pebble is thrown vertically upwards from a bridge with an initial velocity of 4.9 m/s. It strikes the water after 2s. If acceleration due to gravity is `9.8 m//s^(2)(a)` what is the height of the bridge? (b) with what velocity does that pebble strike the water?

Text Solution

Verified by Experts

Let height of the bridge be h then
`h = -4.9 xx 2 + (1)/(2) xx 9.8 xx (2)^(2)`
`rArr h = 9.8 m` `
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