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A projectile is thrown with speed u maki...

A projectile is thrown with speed u making angle `theta` with horizontal at `t=0`. It just crosses the two points at equal height at time `t=1` s and `t=3` sec respectively. Calculate maximum height attained by it. `(g=10 m//s^(2))`

Text Solution

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Displacement in y direction `y= u_y xx 1 - (1)/(2)g xx (1)^(2) = u_y xx 3 - (1)/(2) g(3)^(2) rArr u_y = 2g = 20 m//s`
Maximum height attained `h_(max) = (u_y^(2))/(2g) = 20`m.
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