A player throwsa a ball upwards with an initial speed of `29.4 ms^(-1)`.
(i) What is the direction of acceleration during the upwared motion of the ball?
(ii) What are the velocity and acceleration of the ball at the highest point of its motion?
(iii) Choose the x=0 and t=0 to be the location and time of the ball at its highest point, vertically downward direction to be the positive direction of X-axis, and give the signs of positive, velocity and acceleration of the ball during its upward, and downward motion.
(iv) To what height does the ball rise and after how long does the ball return to the player's hand?( Take g`=9.8 ms^(-2)`, and neglect air resistance).

Explanation

Let's solve the problem step by step:

### Step 1: Direction of Acceleration During Upward Motion
When a ball is thrown upwards, it experiences a constant acceleration due to gravity, which acts downwards. Therefore, the direction of acceleration during the upward motion of the ball is **downwards**.

### Step 2: Velocity and Acceleration at the Highest Point
At the highest point of its motion, the velocity of the ball becomes **0 m/s** because it momentarily stops before descending. However, the acceleration due to gravity remains constant at **9.8 m/s²** downwards.

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