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Show that projection angle 0(o) for a pr...

Show that projection angle `0_(o)` for a projectile launched from the origin is given by :
`0_(o) =tan^(-1) J [(4H_(m))/(R )]" where "H_(m)` =Maximum height, R = Range.

Text Solution

Verified by Experts

`H_m = (u^2 sin^(2) theta_0)/( 2g) , R= (u^(2))/( g) sin 2 theta_0 = (2u^(2)) /(g) sin theta _(0).cos theta_0`
`(H_m) /(R ) = (1)/(4) tan theta _(0) rArr theta_0 = tan ^(-1) ((4H_m)/(R ))`
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