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If the value of universal gravitational ...

If the value of universal gravitational constant is `6.67xx10^(-11) Nm^2 kg^(-2),` then find its value in CGS system.

Text Solution

Verified by Experts

The correct Answer is:
`(6.67 xx 10^(-8) cm^(3)//g s^(2))`
Dimension of gravitational constant = `[ M^(-1)L^(3) T^(-2)]`
`" "n_2= n_1[(M_1)/(M_2)]^(-1) [(L_1)/(L_2)]^(3) [ (T_1)/(T_2)]^(-2)`
here
`" "{:(MKS,,CGS),(n_1 = 6.67 xx 10^(-11),,n_2= ?), (M_1 = kg,,M_2 = g), (L_1 = m,,L_2 = cm), (T_1= sec,, T_2 = sec):}`
`n_2 = 6.67 xx 10^(-11) [ (kg)/(g)]^(-1) [(m)/(cm)]^(3) [(sec)/(sec)]^(2) `
` = 6.67 xx 10^(-11) xx 10^(-3) xx 10^(6) xx 1`
` = 6. 67 xx 10 ^(-8)`
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The value of universal gravitational constant G depends upon :

The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

Knowledge Check

  • The value of universal gravitational constant G=6.67xx10^(-11)Nm^(2)kg^(-2) . The value of G in units of g^(-1)cm^(3)s^(-2) is

    A
    `6.67xx10^(-8)`
    B
    `6.67xx10^(-7)`
    C
    `6.67xx10^(-9)`
    D
    `6.67xx10^(-10)`

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