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The original length of a wire is (153.7 ...

The original length of a wire is `(153.7 pm 0.6)cm.` It is stretched to `(155.3pm 0.2)cm.` Calculate the elongation in the wire with error limits.

Text Solution

Verified by Experts

The correct Answer is:
`( 1.6 pm 0.8)` m
Elongation `= L_2 - L_1`
` " " = (155.3 pm 0.2) - (153.7 pm 0.6)`
`" " (1.6 pm 0.8)` cm
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