Home
Class 11
PHYSICS
The radius of sphere is measured to be (...

The radius of sphere is measured to be `(2.1pm0.5)cm`.Calculate its surface area with error limits.

Text Solution

Verified by Experts

The correct Answer is:
`(55.4 pm 26.4) cm^(2)`
Surface area of sphere = ` 4pi r^(2)`
`= 4xx 3.14 xx (2.1)^(2) = 55.3896 = 55.4 (3 SF)`
`Delta A = 2 (Delta r)/( r ) xxA = 2xx (0.5)/(2.1) xx 55.4 `
`" " = 26. 376 = 26.4 (3SF)`
Promotional Banner

Topper's Solved these Questions

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise BEGINNER S BOX-7|3 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-I UNIT|12 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise BEGINNER S BOX-5|1 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Question|1 Videos

  • SEMICONDUCTORS

    ALLEN|Exercise Part-3(Exercise-4)|51 Videos

Similar Questions

Explore conceptually related problems

The radius of a sphere is measured to be (2.1+-0.5) cm. Calculate its surface area with error limits .

The radius of a sphere is measured to be (2.1+-0.5) cm. Calculate its surface area with error limits .

The radius of a sphere is measured to be (2.1 +- 0.02) cm . Calculate its surface area with error limits.

The radius of a sphere is measured to be (1.2 +- 0.2)cm . Calculate its volume with error limits.

The original length of wire is (153.7 pm 0.6) cm . It is streched to (155.3 pm 0.2) cm. Calculate the elongation in the wire with error limits.

The radius of a sphere is measured as (10 +- 0.02%) cm. The error in the measurement of its volume is

Two rods have lengths measured as (1.8 pm 0.2) m and (2.3 pm 0.1) m. Calculate their combined length with error limits.

If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, find the approximate error in calculating its surface area.

If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximate error in calculating its surface area.

If the radius of a sphere is measured as 9 m with an error of 0.03 m, then find the approximate error in calculating its surface area.