The external and internal diameters of a hollow cylinder are measured to be `(4.23+-0.01)` cm and `(3.89+-0.01)`cm. The thickness of the wall of the cylinder is

Options

A. `(0.34 pm 0.02)` cm
B. `(0.17 pm 0.02)` cm
C. `(0.17 pm 0.01)` cm
D. `(0.34 pm 0.01)` cm

Answer

A

Explanation

Thickness of cylinder can be written as
`t = t pm Delta t`
`t= r_2 - r_1 = 4.23 - 3.89 = 0.34`
`Delta t = Delta r_1 + Delta r_2 = 0.01 + 0.01 = 0.02`
` t (0.34 pm 0.02)` cm