Formula `CH_(3)-(CH_(2))_(14)-COOH` is :-

Options

A. Phospholipid
B. Agrachidonic acid
C. Palmitic acid
D. Triglyceride

Answer

To determine the identity of the compound with the formula CH₃-(CH₂)₁₄-COOH, we can follow these steps:

### Step 1: Analyze the Formula
The formula can be broken down into three parts:
- CH₃ (methyl group)
- (CH₂)₁₄ (a chain of 14 methylene groups)
- COOH (carboxylic acid group)

### Step 2: Count the Carbon Atoms
Counting the carbon atoms:
- The CH₃ contributes 1 carbon.
- The (CH₂)₁₄ contributes 14 carbons.
- The COOH contributes 1 carbon.

Total number of carbon atoms = 1 (from CH₃) + 14 (from CH₂) + 1 (from COOH) = 16 carbon atoms.

### Step 3: Identify the Functional Group
The presence of the COOH group indicates that this compound is a fatty acid, as fatty acids are characterized by having a long hydrocarbon chain and a carboxylic acid group.

### Step 4: Determine the Type of Fatty Acid
Since the hydrocarbon chain consists of 16 carbon atoms, this fatty acid is classified as a saturated fatty acid because there are no double bonds present in the chain.

### Step 5: Name the Fatty Acid
The fatty acid with 16 carbons and no double bonds is known as palmitic acid.

### Conclusion
Thus, the formula CH₃-(CH₂)₁₄-COOH corresponds to palmitic acid.

### Final Answer
The formula CH₃-(CH₂)₁₄-COOH is that of **palmitic acid**.

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