Bouquet stage and synapsis is absent in case of :-

Options

A. Mitosis
B. Heterotypic division
C. Meiosis-I
D. Reductional division

Answer

To determine in which case the bouquet stage and synapsis are absent, we need to analyze the options provided:

1. **Mitosis**: In mitosis, chromosomes do not undergo synapsis, and the bouquet stage is not present. Mitosis involves the separation of sister chromatids without pairing.

2. **Heterotypic Division**: This term is often used to refer to meiosis I, where homologous chromosomes pair and undergo synapsis. Therefore, the bouquet stage is present in this division.

3. **Meiosis I**: During meiosis I, specifically in the leptotene stage, the bouquet stage occurs as the telomeres of chromosomes converge towards the nuclear membrane. Thus, synapsis is also present in this stage.

4. **Reductional Division**: This term typically refers to meiosis, where the chromosome number is reduced by half. Since it includes meiosis I, the bouquet stage and synapsis are also present.

Based on this analysis, the correct answer is **Mitosis**, as it is the only option where both the bouquet stage and synapsis are absent.

### Step-by-Step Solution:
1. **Identify the stages of cell division**: Understand the differences between mitosis and meiosis, particularly meiosis I.
2. **Analyze the options**: Look at each option to see if bouquet stage and synapsis are present or absent.
3. **Mitosis**: Confirm that in mitosis, chromosomes do not pair and thus do not exhibit bouquet stage or synapsis.
4. **Heterotypic Division**: Recognize that this refers to meiosis I, where synapsis occurs.
5. **Meiosis I**: Acknowledge that the bouquet stage occurs in the leptotene stage of meiosis I.
6. **Reductional Division**: Understand that this also refers to meiosis, where both bouquet stage and synapsis are present.
7. **Conclusion**: Conclude that the only option where bouquet stage and synapsis are absent is mitosis.