Number of nuclei participated in the process of double fertilization is :-

Options

A. 2
B. 3
C. 5
D. 6

Answer

To solve the question regarding the number of nuclei that participate in the process of double fertilization, we can break it down into clear steps:

### Step-by-Step Solution:

1. **Understanding Double Fertilization**:
- Double fertilization is a unique process that occurs in angiosperms (flowering plants). It involves the fusion of male and female gametes.

2. **Identifying the Gametes**:
- In double fertilization, two male gametes (sperm cells) enter the embryo sac through the pollen tube.

3. **First Fusion (Syngamy)**:
- One of the male gametes fuses with the egg cell (female gamete).
- The egg cell is haploid (1 nucleus), and the male gamete is also haploid (1 nucleus).
- This fusion results in the formation of a diploid zygote (1 nucleus).

4. **Second Fusion (Triple Fusion)**:
- The second male gamete fuses with the secondary nucleus, which is formed from the fusion of two polar nuclei.
- The secondary nucleus is diploid (2 nuclei), and the male gamete is haploid (1 nucleus).
- This fusion results in the formation of a triploid primary endosperm nucleus (3 nuclei).

5. **Counting the Nuclei**:
- From the first fusion, we have:
- 1 (from the egg cell) + 1 (from the first male gamete) = 2 nuclei
- From the second fusion, we have:
- 2 (from the polar nuclei) + 1 (from the second male gamete) = 3 nuclei
- Therefore, the total number of nuclei involved in double fertilization is:
- 2 (from the first fusion) + 3 (from the second fusion) = 5 nuclei.

### Final Answer:
The number of nuclei that participated in the process of double fertilization is **5**.

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