In monohybrid cross what is the ratio of homozygous dominant and homozygous recessive individuals in `F_(2)` generation :-

Options

A. `1:2:1`
B. `2:1//1:2`
C. `3:1//1:3`
D. `1:1`

Answer

To solve the question regarding the ratio of homozygous dominant and homozygous recessive individuals in the F2 generation of a monohybrid cross, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Monohybrid Cross**:
A monohybrid cross involves two individuals that differ in a single trait. For example, consider a trait controlled by a single gene with two alleles: dominant (T) and recessive (t).

2. **F1 Generation**:
When two homozygous parents are crossed (one homozygous dominant TT and one homozygous recessive tt), all offspring in the F1 generation will be heterozygous (Tt).

3. **Selfing F1 Generation**:
The F1 generation (Tt) is then self-fertilized to produce the F2 generation. The genotypes of the F2 generation can be determined using a Punnett square.

4. **Punnett Square Analysis**:
The Punnett square for Tt x Tt will yield the following genotypes:
- TT (homozygous dominant)
- Tt (heterozygous)
- tt (homozygous recessive)

The resulting genotypic ratio from the Punnett square is:
- 1 TT : 2 Tt : 1 tt

5. **Identifying Homozygous Individuals**:
From the genotypic ratio:
- Homozygous dominant (TT) = 1
- Homozygous recessive (tt) = 1

6. **Calculating the Ratio**:
The ratio of homozygous dominant (TT) to homozygous recessive (tt) individuals in the F2 generation is therefore:
- Ratio = 1 (TT) : 1 (tt)

7. **Conclusion**:
Thus, the final answer to the question is that the ratio of homozygous dominant to homozygous recessive individuals in the F2 generation is 1:1.

### Final Answer:
The ratio of homozygous dominant to homozygous recessive individuals in the F2 generation is **1:1**.

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