What would be the nature of children if a colour blind woman marries a normal man :-

Options

A. Colourblind daughter & normal son
B. Colourblind sons and carrier daughters
C. Normal sons & carrier daughters
D. Normal sons & Normal daughters

Answer

To determine the nature of children when a color-blind woman marries a normal man, we need to understand the genetics behind color blindness, which is an X-linked recessive trait.

### Step-by-Step Solution:

1. **Identify the Genotypes**:
- A color-blind woman has the genotype XcXc (where Xc represents the X chromosome with the color blindness allele).
- A normal man has the genotype XY (where X is the normal X chromosome and Y is the Y chromosome).

2. **Gamete Formation**:
- The color-blind woman can only produce gametes with the Xc chromosome (Xc).
- The normal man can produce two types of gametes: one with the normal X chromosome (X) and one with the Y chromosome (Y).

3. **Possible Combinations**:
- When these gametes combine, the possible offspring genotypes are:
- From Xc (mother) and X (father): XcX (female, carrier)
- From Xc (mother) and Y (father): XcY (male, color blind)

4. **Analyze the Offspring**:
- The female offspring (XcX) will be carriers of the color blindness trait but will not express the trait because they have one normal X chromosome.
- The male offspring (XcY) will express color blindness because they have only one X chromosome, which carries the color blindness allele.

5. **Conclusion**:
- Therefore, the children of a color-blind woman and a normal man will be:
- Color-blind sons (XcY)
- Carrier daughters (XcX)

### Final Answer:
The nature of the children will be color-blind sons and carrier daughters.

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