A dihybrid plant with incomplete linkage on test corss may produce how many types of plants :-

Options

A. 2
B. 4
C. 8
D. 1

Answer

To solve the question of how many types of plants a dihybrid plant with incomplete linkage on a test cross may produce, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Dihybrid Cross**:
- A dihybrid plant is heterozygous for two traits, meaning it has two different genes, each with two alleles. For example, consider genes A and B, where the alleles are A/a and B/b.

2. **Calculate the Number of Gametes**:
- The formula to determine the number of different types of gametes produced by an organism is \(2^n\), where \(n\) is the number of heterozygous gene pairs.
- In a dihybrid cross, \(n = 2\) (since there are two traits).

3. **Apply the Formula**:
- Using the formula:
\[ 2^n = 2^2 = 4 \]
- This means that the dihybrid plant can produce 4 different types of gametes.

4. **Consider Incomplete Linkage**:
- Incomplete linkage means that the genes are not completely independent and may assort together more often than not, but some recombination can still occur.
- In this case, the gametes can be categorized into two parental types and two recombinant types.

5. **Determine the Phenotypes**:
- When a test cross is performed (crossing the dihybrid with a homozygous recessive plant), the resulting offspring will show the phenotypes corresponding to the gametes produced.
- Since there are 4 different types of gametes, this will give rise to 4 different phenotypes.

6. **Final Answer**:
- Therefore, a dihybrid plant with incomplete linkage on a test cross may produce **4 types of plants**.