A normal woman marries an albino man.They have both albino and normal childern .The woman is :

Options

A. Homozygous normal
B. Heterozygous normal
C. Homozygous recessive
D. Homozygous dominant

Answer

To solve the question, we need to analyze the genetic situation presented:

### Step 1: Understanding Albinism
Albinism is an autosomal recessive disorder. This means that an individual must have two copies of the recessive allele (let's denote it as 'a') to express the condition (albino). The normal allele can be denoted as 'A'.

### Step 2: Genotypes of the Parents
- The **albino man** must have the genotype **aa** (homozygous recessive) since he expresses the albino trait.
- The **normal woman** can either be homozygous normal (AA) or heterozygous normal (Aa).

### Step 3: Predicting the Offspring
If the woman were homozygous normal (AA), all children would inherit one normal allele (A) from her and one recessive allele (a) from the albino father, resulting in all children being heterozygous (Aa) and normal. Thus, they would not have any albino children.

However, the question states that they have both albino and normal children. This indicates that some children must have received the recessive allele from both parents.

### Step 4: Analyzing the Offspring's Genotypes
Since there are both albino (aa) and normal (Aa) children, the only way this is possible is if the mother is heterozygous (Aa). In this case:
- The normal children (Aa) receive the normal allele from the mother and the recessive allele from the father.
- The albino children (aa) receive the recessive allele from both parents.

### Conclusion
Since the normal woman must be heterozygous (Aa) to have both albino and normal children, the correct answer is that the woman is **heterozygous normal**.

### Final Answer
The woman is **heterozygous normal (Aa)**.

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