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Parents are carrier for albinism. What w...

Parents are carrier for albinism. What will be the first three children :-

A

Some normal, hetrozygous & albino

B

All normal

C

All heterozygous albino

D

No normal

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The correct Answer is:
To solve the question regarding the potential outcomes for the first three children of parents who are carriers for albinism, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Albinism**: Albinism is an autosomal recessive disorder. This means that an individual must inherit two copies of the recessive allele (aa) to express the disorder. Individuals with one dominant allele (A) and one recessive allele (a) are carriers (Aa) but do not show the disorder. 2. **Genotypes of the Parents**: Since both parents are carriers for albinism, their genotypes can be represented as: - Parent 1: Aa (carrier) - Parent 2: Aa (carrier) 3. **Gamete Formation**: Each parent can produce two types of gametes: - Parent 1 can produce gametes A and a. - Parent 2 can also produce gametes A and a. 4. **Punnett Square**: We can use a Punnett square to determine the possible genotypes of the offspring: ``` A a ---------------- A | AA | Aa | ---------------- a | Aa | aa | ---------------- ``` 5. **Offspring Genotypes**: From the Punnett square, we can see the possible genotypes of the children: - AA (normal, not a carrier) - Aa (normal, carrier) - Aa (normal, carrier) - aa (albino) 6. **Phenotypic Ratios**: The phenotypic ratio of the offspring can be summarized as: - 1 AA (normal) - 2 Aa (normal carriers) - 1 aa (albino) 7. **First Three Children**: Based on the ratios, the first three children could be: - Child 1: Normal (AA) - Child 2: Normal carrier (Aa) - Child 3: Normal carrier (Aa) Alternatively, if we consider the possibility of the order being different, it could also be: - Child 1: Normal carrier (Aa) - Child 2: Normal carrier (Aa) - Child 3: Albino (aa) ### Conclusion: The first three children of parents who are carriers for albinism could be one normal child (AA), two normal carrier children (Aa), and one albino child (aa). The specific order may vary, but the types of children will follow the ratios derived from the Punnett square.
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ALLEN-GENETICS & MOLECULAR BASIS OF INHERITANCE AND MUTATION-EXERCISE-I (CONCEPTUAL QUESTIONS)
  1. A normal woman marries an albino man.They have both albino and normal ...

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  2. Which is a dominant trait ?

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  3. Parents are carrier for albinism. What will be the first three childre...

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  4. Which one is a dominant trait out of the characters chosen by Mendel ?

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  5. In case of taster and non-taster human beings T is for dominance & t i...

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  6. A family has five girls and no son, the probability of the occurance o...

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  7. A tobacco plant heterozygous for recessive character is self-pollinate...

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  8. Which one of the following character in man is controlled by a recessi...

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  9. The migration of gene in to a population from other population by inte...

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  10. What is the probability of three daughters to a couple in three childr...

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  11. The gene for right handedness is dominant over the gene for left hande...

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  12. Probability of four son to a couple is : -

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  13. Down's syndrome is caused by an extra copy of chromosome number 21. Wh...

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  14. A male human is heterozygous for autosomal genes A and B and is also h...

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  15. Given below is a pedigree chart of a family with five children. It sho...

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  16. Equlibrium of gene frequencies is -

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  17. In a Random mating population of 28,800 individuals percentage of domi...

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  18. Pardict from the following chart

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  19. In pedigree analysis symbol Θ used for

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  20. In a population that is in Hardy weinberg equilibrium, the frequency o...

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