A family has five girls and no son, the probability of the occurance of son in `6^(th)` child is :-

Options

A. `1//2`
B. `1//5`
C. 1
D. No chance

Answer

To solve the problem of determining the probability of having a son as the sixth child in a family that already has five girls, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Basics of Sex Determination**:
- In humans, sex is determined by the combination of sex chromosomes. Females have two X chromosomes (XX), while males have one X and one Y chromosome (XY).

2. **Identify the Current Family Composition**:
- The family has five girls and no sons. This means all previous births resulted in females (XX).

3. **Recognize the Independence of Each Birth**:
- The sex of each child is an independent event. The probability of having a boy (XY) or a girl (XX) does not depend on the previous children.

4. **Calculate the Probability for the Sixth Child**:
- The probability of having a boy (son) is 1/2 (50%) and the probability of having a girl (daughter) is also 1/2 (50%).

5. **Conclusion**:
- Therefore, the probability of the occurrence of a son in the sixth child is 1/2.

### Final Answer:
The probability of having a son as the sixth child is **1/2**.

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