If genetic code is tetraplet then what is the possible number of codons wich code 30 types of amino acids :-

Options

A. 261
B. 64
C. 256
D. 43

Answer

To solve the question of how many possible codons can code for 30 types of amino acids when the genetic code is considered to be a tetraplet, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Codons**:
Codons are sequences of nucleotides that correspond to specific amino acids. In a tetraplet code, each codon consists of four nucleotides.

2. **Identify the Nucleotides**:
In this scenario, we have four different nucleotides: A (Adenine), U (Uracil), G (Guanine), and C (Cytosine).

3. **Calculate the Number of Codons**:
Since the genetic code is tetraplet, we need to calculate the total number of possible combinations of these four nucleotides taken four at a time. The formula for this is:
\[ \text{Total Codons} = 4^{n} \]
where \( n \) is the number of nucleotides in each codon. Here, \( n = 4 \).

4. **Perform the Calculation**:
Plugging in the values:
\[ \text{Total Codons} = 4^{4} = 256 \]

5. **Interpret the Result**:
The result indicates that there are 256 possible codons. Since this number is greater than the 30 types of amino acids mentioned in the question, it implies that these codons can code for all 30 types of amino acids.

6. **Conclusion**:
Therefore, the possible number of codons that can code for 30 types of amino acids, given that the genetic code is tetraplet, is 256.

### Final Answer:
The possible number of codons which can code for 30 types of amino acids is **256**.

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