How many different kinds of gametes will be produced by a plant having the genotype AaBBCC?

Options

A. Three
B. Four
C. Nine
D. Two

Answer

To determine how many different kinds of gametes will be produced by a plant with the genotype AaBBCC, we can follow these steps:

### Step 1: Identify the Genotype
The given genotype is AaBBCC. Here, we can see that:
- A is heterozygous (Aa)
- B is homozygous (BB)
- C is homozygous (CC)

### Step 2: Count the Number of Heterozygous Alleles
In the genotype, we need to identify how many alleles are heterozygous. A heterozygous allele has two different forms (e.g., Aa). In this case, we have:
- 1 heterozygous pair (Aa)

### Step 3: Use the Formula for Gametes
The formula to calculate the number of different kinds of gametes produced is:
\[ \text{Number of gametes} = 2^n \]
where \( n \) is the number of heterozygous pairs.

### Step 4: Substitute the Value of n
From Step 2, we found that \( n = 1 \) (since there is only one heterozygous pair, Aa). Now we can substitute this value into the formula:
\[ \text{Number of gametes} = 2^1 = 2 \]

### Step 5: List the Possible Gametes
Now, let's identify the actual gametes formed:
1. From the heterozygous pair Aa, we can get either A or a.
2. From the homozygous pair BB, we can only get B.
3. From the homozygous pair CC, we can only get C.

Thus, the possible combinations of gametes are:
- Gamete 1: ABC (from A, B, C)
- Gamete 2: abc (from a, B, C)

### Final Answer
Therefore, the total number of different kinds of gametes produced by the plant with the genotype AaBBCC is **2**.

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