In cells of superfemale with 47 chromosomes (44 + xxx) visible barr bodies are :-

Options

A. 1
B. 0
C. 2
D. 3

Answer

To solve the question regarding the number of visible Barr bodies in cells of a superfemale with 47 chromosomes (44 + XXX), we can follow these steps:

### Step-by-Step Solution:

1. **Understand Barr Bodies**: Barr bodies are inactivated X chromosomes in females. Typically, in a normal female with two X chromosomes (XX), one X chromosome is active, and the other is inactivated, resulting in one Barr body.

2. **Identify the Karyotype**: The karyotype given is 44 + XXX, which indicates that there are 44 autosomes and three X chromosomes.

3. **Calculate the Number of Barr Bodies**: The formula to determine the number of Barr bodies is:
\[ \text{Number of Barr Bodies} = \text{Number of X chromosomes} - 1 \]
In this case, we have 3 X chromosomes (from XXX).

4. **Apply the Formula**:
\[ \text{Number of Barr Bodies} = 3 - 1 = 2 \]

5. **Conclusion**: Therefore, in the cells of a superfemale with a karyotype of 44 + XXX, there are 2 visible Barr bodies.

### Final Answer:
The number of visible Barr bodies in the cells of a superfemale with 47 chromosomes (44 + XXX) is **2**.

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