If `3^(n)` is the theoretically possible number of different genotypes (when n= the number of chromosome pairs with each carrying one pairs of heterzygous alleles), the different genotypes produced by pea plant is :

Options

A. `3^(10)`
B. `3^(12)`
C. `3^(14)`
D. `3^(7)`

Answer

To solve the question regarding the number of different genotypes produced by pea plants, we will follow these steps:

### Step-by-Step Solution:

1. **Understand the Formula**: The number of different genotypes is given by the formula \(3^n\), where \(n\) is the number of chromosome pairs that are heterozygous.

2. **Identify the Number of Heterozygous Pairs**: According to the video transcript, there are 7 varieties of heterozygous alleles in the pea plants. This means \(n = 7\).

3. **Apply the Formula**: Substitute \(n\) into the formula:
\[ \text{Number of genotypes} = 3^n = 3^7 \]

4. **Calculate \(3^7\)**:
- First, calculate \(3^2 = 9\)
- Then, \(3^3 = 27\)
- Next, \(3^4 = 81\)
- Continuing, \(3^5 = 243\)
- Then, \(3^6 = 729\)
- Finally, \(3^7 = 2187\)

5. **Conclusion**: Therefore, the theoretically possible number of different genotypes produced by the pea plant is \(2187\).

### Final Answer:
The different genotypes produced by the pea plant is \(2187\).

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