Consider the following sequence on m-RNA AUGGCAGUGCCA. Assuming that genetic code is overlap then how many number of codon may be present on this genetic code

Options

A. 9
B. 10
C. 8
D. 11

Answer

To determine how many codons may be present in the given mRNA sequence (AUGGCAGUGCCA) under the assumption that the genetic code is overlapping, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the mRNA Sequence:**
The given mRNA sequence is: AUGGCAGUGCCA.

2. **Understand Codons:**
A codon consists of three nucleotides (triplet). In a normal (non-overlapping) scenario, the sequence would be divided into codons without any overlap. However, since the question specifies that the genetic code is overlapping, we need to consider how the codons can overlap.

3. **Count the Total Nucleotides:**
The total number of nucleotides in the sequence is 12 (AUGGCAGUGCCA).

4. **Determine the Overlapping Codons:**
In an overlapping codon scenario, each new codon starts from the second nucleotide of the previous codon. This means:
- The first codon is from nucleotides 1-3: AUG
- The second codon is from nucleotides 2-4: UGG
- The third codon is from nucleotides 3-5: GGC
- The fourth codon is from nucleotides 4-6: GCA
- The fifth codon is from nucleotides 5-7: CAG
- The sixth codon is from nucleotides 6-8: AGU
- The seventh codon is from nucleotides 7-9: GUG
- The eighth codon is from nucleotides 8-10: UGC
- The ninth codon is from nucleotides 9-11: GCC
- The tenth codon is from nucleotides 10-12: CCA

5. **Count the Codons:**
From the above overlapping codons, we can see that there are a total of 10 codons.

6. **Final Answer:**
Therefore, the total number of codons present in this overlapping genetic code is **10**.