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In family papilionaaceae(fabaceae),5 pet...

In family papilionaaceae(fabaceae),5 petals from a unique association, In which 3 different elements participate , these are standard (vexillum) , wings (alae) & Keel (carina). What is the number of these elements :-

A

1,2,2 respectively

B

2,1,2 respectively

C

1,1,3 respectively

D

2,2,1 respectively

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To solve the question regarding the number of elements in the flower structure of the family Papilionaceae (Fabaceae), we need to analyze the components of the flower petals. ### Step-by-Step Solution: 1. **Identify the Flower Structure**: In the Papilionaceae family, the flower typically consists of five petals that are arranged in a specific manner. 2. **Recognize the Three Elements**: The five petals are categorized into three distinct elements: - **Standard (Vexillum)**: This is the largest petal and is usually positioned at the top. There is only **one** standard petal. - **Wings (Alae)**: These are two smaller petals located on either side of the standard petal. There are **two** wing petals. - **Keel (Carina)**: This consists of two petals that are fused together, forming a structure that resembles a boat. There are **two** keel petals. 3. **Count the Total Elements**: - Standard: 1 - Wings: 2 - Keel: 2 (counted as one unit since they are fused) Therefore, the total number of petals is 5, which can be broken down as: - 1 (Standard) + 2 (Wings) + 2 (Keel) = 5 petals. 4. **Conclusion**: The number of elements participating in the unique association of petals in the Papilionaceae family is three: one standard, two wings, and two keels. ### Final Answer: The number of these elements is **three**: Standard (1), Wings (2), and Keel (2). ---
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