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The sum sum(n=1)^oo tan^(-1)(3/(n^2+n-1)...

The sum `sum_(n=1)^oo tan^(-1)(3/(n^2+n-1))` is equal to

A

`(pi)/2+tan^(-1)(3)`

B

`(pi)/2`

C

`pi-tan^(-1)(3)`

D

`(pi)/2-tan^(-1)(3)`

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