What mass of NaCl would be decomposed by 98 g of `H_(2)SO_(4)` if 120 g of `NaHSO_(4)` and 27 .5 g of HCl are produced in a reaction. Assuming that law of mass conservation is true :

Options

A. 4.95 g
B. 49 .5 g
C. 0. 495 g
D. 495 g

Answer

To solve the problem, we will apply the law of conservation of mass, which states that the mass of the reactants must equal the mass of the products in a chemical reaction.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Mass of `H₂SO₄` used = 98 g
- Mass of `NaHSO₄` produced = 120 g
- Mass of `HCl` produced = 27.5 g

2. **Write the Law of Conservation of Mass Equation:**
According to the law of conservation of mass:
\[ \text{Mass of reactants} = \text{Mass of products} \]
In our case, the reactants are `NaCl` and `H₂SO₄`, and the products are `NaHSO₄` and `HCl`.

3. **Set Up the Equation:**
Let the mass of `NaCl` that decomposes be \( x \) grams. Therefore, we can write:
\[ x + 98 = 120 + 27.5 \]

4. **Calculate the Total Mass of Products:**
\[ 120 + 27.5 = 147.5 \text{ g} \]

5. **Substitute and Solve for \( x \):**
Now, substituting the total mass of products into the equation:
\[ x + 98 = 147.5 \]
Rearranging gives:
\[ x = 147.5 - 98 \]
\[ x = 49.5 \text{ g} \]

6. **Conclusion:**
The mass of `NaCl` that would be decomposed is **49.5 g**.

### Final Answer:
The mass of NaCl decomposed is **49.5 g**.

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